Websites on Fermat's Last Theorem: Beal Conjecture The official Beal Conjecture site with information and links regarding the problem. The Beal Conjecture $75,000 prized problem pertaining to the Diophantine equation of the form A^x + B^y = C^z where A, B, C, x, y and z are positive integers and x, y and z are all greater than 2, then A, B and C must have a common factor. Beal's Conjecture: A Search for Counterexamples Results of a computer search by Peter Norvig. Beal's Conjecture Disproved Disproved for the same reasons Fermat's Last Theorem is proved by a binomial infinite series expansion An Elementary Attack on "Fermat" By Kerry M. Evans. Fermat Corner Fermat's Last Theorem by Simon Singh. Discusses the early and recent history of people trying to solve this perplexing problem, including Andrew Wiles' final success. Includes information about poems, limericks, the off-Broadway show and a quiz. Fermat's Last Theorem A historical and biographical account. Fermat's Last Theorem -- from MathWorld Article in Eric Weisstein's World of Mathematics. Is Fermat's Last Theorem Proven? An attempted elementary proof of Fermat's Last Theorem by James Constant, rejecting that of Wiles. NOVA Online | The Proof NOVA Online presents The Proof, including an interview with Andrew Wiles, an essay on Sophie Germain, and the Pythagorean theorem. On the Beal Conjecture An elementary proof of Beal's Conjecture given the proof of Fermat's Last Theorem. Proof of Fermat's Last Theorem An attempted elementary proof of FLT using binomial expansions. The Solving of Fermat's Last Theorem Slides for a talk by Karl Rubin on the story of Fermat's Last Theorem for a general audience, including the history of the problem, the story of Andrew Wiles' solution and the excitement surrounding it, and some of the many ideas used in his proof. Was Wiles' Proof Really First? Edited from the book "Fermat's last theorem proved" by Nico de Jong (1992). Wiles, Ribet, Shimura-Taniyama-Weil and FLT A collection of links based on the former e-math gopher archive.
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